Optimal. Leaf size=150 \[ \frac{2 (e x)^{m+1} \sqrt{1-e^{2 i a d} \left (c x^n\right )^{2 i b d}} \text{Hypergeometric2F1}\left (\frac{1}{2},-\frac{-b d n+2 i m+2 i}{4 b d n},-\frac{-5 b d n+2 i m+2 i}{4 b d n},e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{e (i b d n+2 m+2) \sqrt{\sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}} \]
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Rubi [A] time = 0.109999, antiderivative size = 150, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.13, Rules used = {4493, 4491, 364} \[ \frac{2 (e x)^{m+1} \sqrt{1-e^{2 i a d} \left (c x^n\right )^{2 i b d}} \, _2F_1\left (\frac{1}{2},-\frac{2 i m-b d n+2 i}{4 b d n};-\frac{2 i m-5 b d n+2 i}{4 b d n};e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{e (i b d n+2 m+2) \sqrt{\sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}} \]
Antiderivative was successfully verified.
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Rule 4493
Rule 4491
Rule 364
Rubi steps
\begin{align*} \int \frac{(e x)^m}{\sqrt{\sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}} \, dx &=\frac{\left ((e x)^{1+m} \left (c x^n\right )^{-\frac{1+m}{n}}\right ) \operatorname{Subst}\left (\int \frac{x^{-1+\frac{1+m}{n}}}{\sqrt{\sin (d (a+b \log (x)))}} \, dx,x,c x^n\right )}{e n}\\ &=\frac{\left ((e x)^{1+m} \left (c x^n\right )^{-\frac{1}{2} i b d-\frac{1+m}{n}} \sqrt{1-e^{2 i a d} \left (c x^n\right )^{2 i b d}}\right ) \operatorname{Subst}\left (\int \frac{x^{-1+\frac{i b d}{2}+\frac{1+m}{n}}}{\sqrt{1-e^{2 i a d} x^{2 i b d}}} \, dx,x,c x^n\right )}{e n \sqrt{\sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}}\\ &=\frac{2 (e x)^{1+m} \sqrt{1-e^{2 i a d} \left (c x^n\right )^{2 i b d}} \, _2F_1\left (\frac{1}{2},-\frac{2 i+2 i m-b d n}{4 b d n};-\frac{2 i+2 i m-5 b d n}{4 b d n};e^{2 i a d} \left (c x^n\right )^{2 i b d}\right )}{e (2+2 m+i b d n) \sqrt{\sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}}\\ \end{align*}
Mathematica [A] time = 0.517193, size = 131, normalized size = 0.87 \[ -\frac{2 x (e x)^m \left (-1+e^{2 i d \left (a+b \log \left (c x^n\right )\right )}\right ) \text{Hypergeometric2F1}\left (1,-\frac{-3 b d n+2 i m+2 i}{4 b d n},-\frac{-5 b d n+2 i m+2 i}{4 b d n},e^{2 i d \left (a+b \log \left (c x^n\right )\right )}\right )}{(i b d n+2 m+2) \sqrt{\sin \left (d \left (a+b \log \left (c x^n\right )\right )\right )}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.263, size = 0, normalized size = 0. \begin{align*} \int{ \left ( ex \right ) ^{m}{\frac{1}{\sqrt{\sin \left ( d \left ( a+b\ln \left ( c{x}^{n} \right ) \right ) \right ) }}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e x\right )^{m}}{\sqrt{\sin \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e x\right )^{m}}{\sqrt{\sin{\left (a d + b d \log{\left (c x^{n} \right )} \right )}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (e x\right )^{m}}{\sqrt{\sin \left ({\left (b \log \left (c x^{n}\right ) + a\right )} d\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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